University of Washington Truth Table Problem Solving Questions
Question Description
I’m working on a c++ multi-part question and need an explanation and answer to help me learn.
Solve the following problems :
a. Negate ∀n∃m(2m = n) and show it in a form that does not include the NOT operator.
b. Draw the truth table for (P && (P -> Q)) -> Q
c. Simplify the following code as much as possible:
if ((x >0 && x<y) || (x >0 && x >=y)) {
x=y;
}
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